blob: 4ae424ce0f3c89244ba5b0db7c1ce294c6172d09 [file] [log] [blame]
/* This testcase is part of GDB, the GNU debugger.
Copyright 2014-2021 Free Software Foundation, Inc.
This program is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>. */
#include <pthread.h>
#include <unistd.h>
#include <stdlib.h>
pthread_barrier_t barrier;
pthread_t child_thread;
volatile unsigned int counter = 1;
volatile unsigned int watch_me;
volatile unsigned int other;
void *
child_function (void *arg)
{
pthread_barrier_wait (&barrier);
while (counter > 0)
{
counter++;
watch_me = 1; /* set breakpoint child here */
other = 1;
usleep (1);
}
pthread_exit (NULL);
}
int
main ()
{
int res;
long i;
alarm (300);
pthread_barrier_init (&barrier, NULL, 2);
res = pthread_create (&child_thread, NULL, child_function, NULL);
pthread_barrier_wait (&barrier);
/* Use an infinite loop with no function calls so that "step" over
this line never finishes before the watchpoint in the other
thread triggers. That can happen if the step-over of thread 2 is
done with displaced stepping on a target that is always in
non-stop mode, as in that case GDB runs both threads
simultaneously. */
while (1); /* set wait-thread breakpoint here */
pthread_join (child_thread, NULL);
exit (EXIT_SUCCESS);
}