! { dg-do run } | |
! Check the fix for PR28005, in which the mechanism for dealing | |
! with matmul (transpose (a), b) would cause wrong results for | |
! matmul (a(i, 1:n), b(1:n, 1:n)). | |
! | |
! Based on the original testcase contributed by | |
! Tobias Burnus <tobias.burnus@physik.fu-berlin.de> | |
! | |
implicit none | |
integer, parameter :: nmax = 3 | |
integer :: i, n = 2 | |
integer, dimension(nmax,nmax) :: iB=0 , iC=1 | |
integer, dimension(nmax,nmax) :: iX1=99, iX2=99, iChk | |
iChk = reshape((/30,66,102,36,81,126,42,96,150/),(/3,3/)) | |
! This would give 3, 3, 99 | |
iB = reshape((/1 ,3 ,0 ,2 ,5 ,0 ,0 ,0 ,0 /),(/3,3/)) | |
iX1(1:n,1) = matmul( iB(2,1:n),iC(1:n,1:n) ) | |
! This would give 4, 4, 99 | |
ib(3,1) = 1 | |
iX2(1:n,1) = matmul( iB(2,1:n),iC(1:n,1:n) ) | |
! Whereas, we should have 8, 8, 99 | |
if (any (iX1(1:n+1,1) .ne. (/8, 8, 99/))) STOP 1 | |
if (any (iX1 .ne. iX2)) STOP 2 | |
! Make sure that the fix does not break transpose temporaries. | |
iB = reshape((/(i, i = 1, 9)/),(/3,3/)) | |
ic = transpose (iB) | |
iX1 = transpose (iB) | |
iX1 = matmul (iX1, iC) | |
iX2 = matmul (transpose (iB), iC) | |
if (any (iX1 .ne. iX2)) STOP 3 | |
if (any (iX1 .ne. iChk)) STOP 4 | |
end |