| // Bug: g++ doesn't find the conversion from ostream_withassign to ostream. | |
| #include <iostream.h> | |
| template <class T> | |
| struct A { | |
| T t; | |
| }; | |
| template <class T> | |
| ostream & operator<< (ostream & os, A<T> & a) | |
| { | |
| os << a.t; | |
| return os; | |
| } | |
| int main () | |
| { | |
| A<int> a = { 1 }; | |
| cout << a << endl; | |
| } |