| // ignore-tidy-undocumented-unsafe | |
| use crate::cmp; | |
| use crate::mem::{self, MaybeUninit}; | |
| use crate::ptr; | |
| /// Rotates the range `[mid-left, mid+right)` such that the element at `mid` becomes the first | |
| /// element. Equivalently, rotates the range `left` elements to the left or `right` elements to the | |
| /// right. | |
| /// | |
| /// # Safety | |
| /// | |
| /// The specified range must be valid for reading and writing. | |
| /// | |
| /// # Algorithm | |
| /// | |
| /// Algorithm 1 is used for small values of `left + right` or for large `T`. The elements are moved | |
| /// into their final positions one at a time starting at `mid - left` and advancing by `right` steps | |
| /// modulo `left + right`, such that only one temporary is needed. Eventually, we arrive back at | |
| /// `mid - left`. However, if `gcd(left + right, right)` is not 1, the above steps skipped over | |
| /// elements. For example: | |
| /// ```text | |
| /// left = 10, right = 6 | |
| /// the `^` indicates an element in its final place | |
| /// 6 7 8 9 10 11 12 13 14 15 . 0 1 2 3 4 5 | |
| /// after using one step of the above algorithm (The X will be overwritten at the end of the round, | |
| /// and 12 is stored in a temporary): | |
| /// X 7 8 9 10 11 6 13 14 15 . 0 1 2 3 4 5 | |
| /// ^ | |
| /// after using another step (now 2 is in the temporary): | |
| /// X 7 8 9 10 11 6 13 14 15 . 0 1 12 3 4 5 | |
| /// ^ ^ | |
| /// after the third step (the steps wrap around, and 8 is in the temporary): | |
| /// X 7 2 9 10 11 6 13 14 15 . 0 1 12 3 4 5 | |
| /// ^ ^ ^ | |
| /// after 7 more steps, the round ends with the temporary 0 getting put in the X: | |
| /// 0 7 2 9 4 11 6 13 8 15 . 10 1 12 3 14 5 | |
| /// ^ ^ ^ ^ ^ ^ ^ ^ | |
| /// ``` | |
| /// Fortunately, the number of skipped over elements between finalized elements is always equal, so | |
| /// we can just offset our starting position and do more rounds (the total number of rounds is the | |
| /// `gcd(left + right, right)` value). The end result is that all elements are finalized once and | |
| /// only once. | |
| /// | |
| /// Algorithm 2 is used if `left + right` is large but `min(left, right)` is small enough to | |
| /// fit onto a stack buffer. The `min(left, right)` elements are copied onto the buffer, `memmove` | |
| /// is applied to the others, and the ones on the buffer are moved back into the hole on the | |
| /// opposite side of where they originated. | |
| /// | |
| /// Algorithms that can be vectorized outperform the above once `left + right` becomes large enough. | |
| /// Algorithm 1 can be vectorized by chunking and performing many rounds at once, but there are too | |
| /// few rounds on average until `left + right` is enormous, and the worst case of a single | |
| /// round is always there. Instead, algorithm 3 utilizes repeated swapping of | |
| /// `min(left, right)` elements until a smaller rotate problem is left. | |
| /// | |
| /// ```text | |
| /// left = 11, right = 4 | |
| /// [4 5 6 7 8 9 10 11 12 13 14 . 0 1 2 3] | |
| /// ^ ^ ^ ^ ^ ^ ^ ^ swapping the right most elements with elements to the left | |
| /// [4 5 6 7 8 9 10 . 0 1 2 3] 11 12 13 14 | |
| /// ^ ^ ^ ^ ^ ^ ^ ^ swapping these | |
| /// [4 5 6 . 0 1 2 3] 7 8 9 10 11 12 13 14 | |
| /// we cannot swap any more, but a smaller rotation problem is left to solve | |
| /// ``` | |
| /// when `left < right` the swapping happens from the left instead. | |
| pub unsafe fn ptr_rotate<T>(mut left: usize, mut mid: *mut T, mut right: usize) { | |
| type BufType = [usize; 32]; | |
| if mem::size_of::<T>() == 0 { | |
| return; | |
| } | |
| loop { | |
| // N.B. the below algorithms can fail if these cases are not checked | |
| if (right == 0) || (left == 0) { | |
| return; | |
| } | |
| if (left + right < 24) || (mem::size_of::<T>() > mem::size_of::<[usize; 4]>()) { | |
| // Algorithm 1 | |
| // Microbenchmarks indicate that the average performance for random shifts is better all | |
| // the way until about `left + right == 32`, but the worst case performance breaks even | |
| // around 16. 24 was chosen as middle ground. If the size of `T` is larger than 4 | |
| // `usize`s, this algorithm also outperforms other algorithms. | |
| let x = unsafe { mid.sub(left) }; | |
| // beginning of first round | |
| let mut tmp: T = unsafe { x.read() }; | |
| let mut i = right; | |
| // `gcd` can be found before hand by calculating `gcd(left + right, right)`, | |
| // but it is faster to do one loop which calculates the gcd as a side effect, then | |
| // doing the rest of the chunk | |
| let mut gcd = right; | |
| // benchmarks reveal that it is faster to swap temporaries all the way through instead | |
| // of reading one temporary once, copying backwards, and then writing that temporary at | |
| // the very end. This is possibly due to the fact that swapping or replacing temporaries | |
| // uses only one memory address in the loop instead of needing to manage two. | |
| loop { | |
| tmp = unsafe { x.add(i).replace(tmp) }; | |
| // instead of incrementing `i` and then checking if it is outside the bounds, we | |
| // check if `i` will go outside the bounds on the next increment. This prevents | |
| // any wrapping of pointers or `usize`. | |
| if i >= left { | |
| i -= left; | |
| if i == 0 { | |
| // end of first round | |
| unsafe { x.write(tmp) }; | |
| break; | |
| } | |
| // this conditional must be here if `left + right >= 15` | |
| if i < gcd { | |
| gcd = i; | |
| } | |
| } else { | |
| i += right; | |
| } | |
| } | |
| // finish the chunk with more rounds | |
| for start in 1..gcd { | |
| tmp = unsafe { x.add(start).read() }; | |
| i = start + right; | |
| loop { | |
| tmp = unsafe { x.add(i).replace(tmp) }; | |
| if i >= left { | |
| i -= left; | |
| if i == start { | |
| unsafe { x.add(start).write(tmp) }; | |
| break; | |
| } | |
| } else { | |
| i += right; | |
| } | |
| } | |
| } | |
| return; | |
| // `T` is not a zero-sized type, so it's okay to divide by its size. | |
| } else if cmp::min(left, right) <= mem::size_of::<BufType>() / mem::size_of::<T>() { | |
| // Algorithm 2 | |
| // The `[T; 0]` here is to ensure this is appropriately aligned for T | |
| let mut rawarray = MaybeUninit::<(BufType, [T; 0])>::uninit(); | |
| let buf = rawarray.as_mut_ptr() as *mut T; | |
| let dim = unsafe { mid.sub(left).add(right) }; | |
| if left <= right { | |
| unsafe { | |
| ptr::copy_nonoverlapping(mid.sub(left), buf, left); | |
| ptr::copy(mid, mid.sub(left), right); | |
| ptr::copy_nonoverlapping(buf, dim, left); | |
| } | |
| } else { | |
| unsafe { | |
| ptr::copy_nonoverlapping(mid, buf, right); | |
| ptr::copy(mid.sub(left), dim, left); | |
| ptr::copy_nonoverlapping(buf, mid.sub(left), right); | |
| } | |
| } | |
| return; | |
| } else if left >= right { | |
| // Algorithm 3 | |
| // There is an alternate way of swapping that involves finding where the last swap | |
| // of this algorithm would be, and swapping using that last chunk instead of swapping | |
| // adjacent chunks like this algorithm is doing, but this way is still faster. | |
| loop { | |
| unsafe { | |
| ptr::swap_nonoverlapping(mid.sub(right), mid, right); | |
| mid = mid.sub(right); | |
| } | |
| left -= right; | |
| if left < right { | |
| break; | |
| } | |
| } | |
| } else { | |
| // Algorithm 3, `left < right` | |
| loop { | |
| unsafe { | |
| ptr::swap_nonoverlapping(mid.sub(left), mid, left); | |
| mid = mid.add(left); | |
| } | |
| right -= left; | |
| if right < left { | |
| break; | |
| } | |
| } | |
| } | |
| } | |
| } |