// { dg-do run } | |
// Bug: g++ doesn't find the conversion from ostream_withassign to ostream. | |
#include <iostream> | |
template <class T> | |
struct A { | |
T t; | |
}; | |
template <class T> | |
std::ostream & operator<< (std::ostream & os, A<T> & a) | |
{ | |
os << a.t; | |
return os; | |
} | |
int main () | |
{ | |
A<int> a = { 1 }; | |
std::cout << a << std::endl; | |
} | |